6,3x+x^2=101

Solution for 6,3x+x^2=101 equation:

6.3x+x^2=101

We move all terms to the left:

6.3x+x^2-(101)=0

a = 1; b = 6.3; c = -101;
Δ = b2-4ac
Δ = 6.32-4·1·(-101)
Δ = 443.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.3)-\sqrt{443.69}}{2*1}=\frac{-6.3-\sqrt{443.69}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.3)+\sqrt{443.69}}{2*1}=\frac{-6.3+\sqrt{443.69}}{2}
$